(x^2-4)(x+1)=y

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Solution for (x^2-4)(x+1)=y equation:


Simplifying
(x2 + -4)(x + 1) = y

Reorder the terms:
(-4 + x2)(x + 1) = y

Reorder the terms:
(-4 + x2)(1 + x) = y

Multiply (-4 + x2) * (1 + x)
(-4(1 + x) + x2(1 + x)) = y
((1 * -4 + x * -4) + x2(1 + x)) = y
((-4 + -4x) + x2(1 + x)) = y
(-4 + -4x + (1 * x2 + x * x2)) = y
(-4 + -4x + (1x2 + x3)) = y
(-4 + -4x + 1x2 + x3) = y

Solving
-4 + -4x + 1x2 + x3 = y

Solving for variable 'x'.

Combine like terms: y + -1y = 0
-4 + -4x + 1x2 + x3 + -1y = 0

The solution to this equation could not be determined.

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